Kotlin program to check if a number is a palindrome

Comprehensive Collection of Kotlin Examples

In this program, you will learn how to check if a number is a palindrome in Kotlin. This is done by using a while loop.

Example: Check the palindrome program

fun main(args: Array<String>) {
　　　　var num =　121
　　　　var reversedInteger = 0
　　　　var remainder: Int
　　　　val originalInteger: Int
　　　　originalInteger = num
　　　　//The reversed integer is stored in the variable
　　　　while (num != 0) {
　　　　　　　　remainder = num %　10
　　　　　　　　reversedInteger = reversedInteger　*　10　+　remainder
　　　　　　　　num　/=　10
　　　　}
　　　　//If orignalInteger and reversedInteger are equal, then it is a palindrome
　　　　if (originalInteger == reversedInteger)
　　　　　　　　println("$originalInteger is a palindrome.")
　　　　else
　　　　　　　　println("$originalInteger is not a palindrome.")
}

When running this program, the output is:

121　Is a palindrome.

Note:You can change the value of num to11221Then, when running the program, the output is:

11221　Is not a palindrome.

The following is the equivalent Java code:Check the Java program for palindrome numbers

In this program

• First, the value of the given number (num) is stored in another integeroriginalIntegerin the variable. This is because we need to compare the value of the reversed number with the original number at the end.

• Then, use a while loop to iterate over num until it equals 0.

• In each iteration, the last digit of num is stored in remainder.

• Then, add the remainder to reversedInteger, so that it can be added to the next position value (multiply by10).

• Then, divide by10Then, remove the last digit from num.

• Finally, compare reversedInteger and originalInteger. If they are equal, then it is a palindrome number. If not, then it is not.

The following are the steps to be executed:

Comprehensive Collection of Kotlin Examples