Python program to find Armstrong numbers in integers

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Example of finding all Armstrong numbers between two integers. To solve this problem, we used nested loops and if statements.

To understand this example, you should understand the followingPython programmingTopic:

• Python if ... else statement

• Python while loop

A positive integer is called an Armstrong order, n if

abcd... = an　+　bn　+　cn　+　dn　+　...

For example,

153　=　1*1*1　+　5*5*5　+　3*3*3　　//　153　is an Armstrong number.

Visit this page to learn howCheck if a number is an Armstrong number in Python.

Source code

# Python program to find Armstrong numbers in integers
lower =　100
upper =　2000
for num in range(lower, upper　+　1)
　　　# order number
　　　order = len(str(num))
　　　　
　　　# Initialize sum
　　　sum = 0
　　　temp = num
　　　while temp > 0:
　　　　　　　digit = temp %　10
　　　　　　　sum　+= digit　**　order
　　　　　　　temp　//=　10
　　　if num == sum:
　　　　　　　print(num)

Output result

153
370
371
407
1634

Here, we set the lower limit in the variable lower100, and the upper limit was set in the variable upper2000. We used a for loop to iterate from the variable lower to upper. In the iteration, the value of lower increases1, and check if it is an Armstrong number.

You can change the range and test by changing the variables lower and upper. Please note that the variable lower should be less than upper for this program to run properly.

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