Python program to check leap year

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In this program, you will learn to check if a year is a leap year. We will use nested if ... else to solve this problem.

To understand this example, you should understand the followingPython programmingTopic:

• Python operators

• Python if ... else statement

Leap years can be4divisible, except for centennial years (years ending in 00). Only those that can be completely4Leap years are exactly divisible by 00, for example,

2017　Is not a leap year
1900 is not a leap year
2012　Leap year
2000 is a leap year

Source code

# Python program to check if a year is a leap year
year =　2000
# Get year from user (integer input)
# year = int(input("Enter year: "))
if (year %　4) == 0:
　　　if (year %　100) == 0:
　　　　　　　if (year %　400) == 0:
　　　　　　　　　　　print("{0} is a leap year".format(year))
　　　　　　　else:
　　　　　　　　　　　print("{0} is not a leap year".format(year))
　　　else:
　　　　　　　print("{0} is a leap year".format(year))
else:
　　　print("{0} is not a leap year".format(year))

Output result

2000 is a leap year

You can change the value of the year in the source code, then run the program again to test it.

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