C program cyclically uses by reference call to swap elements

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In this example, we use by reference call to cyclically swap the three numbers entered by the user.

To understand this example, you should understand the followingC Programming LanguageTopic:

• C pointers

• C by reference call: using pointers

The program swaps elements by reference call

#include <stdio.h>
void cyclicSwap(int　*a, int　*b, int　*c);
int main() {
　　　　int a, b, c;
　　　　printf("Enter a, b, and c: ");
　　　　scanf("%d %d %d", &a, &b, &c);
　　　　printf("The values before swapping:\n");
　　　　printf("a = %d 
b = %d 
c = %d\n", a, b, c);
　　　　cyclicSwap(&a, &b, &c);
　　　　printf("The values after swapping:\n");
　　　　printf("a = %d 
b = %d 
c = %d", a, b, c);
　　　　return 0;
}
//Circular swap
void cyclicSwap(int　*n1, int　*n2, int　*n3) {
　　　　int temp;
　　　　temp =　*n2;
　　　　*n2　=　*n1;
　　　　*n1　=　*n3;
　　　　*n3　= temp;
}

Output result

Enter a, b, and c separately:　1
2
3
The values before swapping:
a =　1　
b =　2　
c =　3
The values after swapping:
a =　3　
b =　1　
c =　2

Here, the three numbers entered by the user are stored in variables a, b, and c. The addresses of these numbers will be passed to the cyclicSwap() function.

cyclicSwap(&a, &b, &c);

In the function definition of cyclicSwap(), we have assigned these addresses to pointers.

cyclicSwap(int　*n1, int　*n2, int　*n3) {
　　　　...
}

When n in cyclicSwap()1and n2and n3When the values of a, b, and c in main() change.

Note:The cyclicSwap() function does not return anything.

Comprehensive Collection of C Programming Examples