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C ++ The list concatenation function is used to transfer elements from the list y to the specified position in the list container, which causes the size of both lists to change.
void splice(iterator pos, list& y); void splice(iterator pos, list& y, iterator pos1); void splice(iterator pos, list& y, iterator first, iterator last);
y: It is a list object of the same content transmission type.
pos: It defines the position where the y element is inserted.
pos1:pos1The elements pointed to will be transmitted.
(first, last): It defines the range of elements to be transmitted.
It does not return any value.
Let's look at a simple example
#include<iostream> #include<list> using namespace std; int main() { list<int> li={1,2,3,4}; list<int> li1={5,6,7,8}; list<int>::iterator itr=li.begin(); li.splice(itr,li1); for(list<int>::iterator itr=li.begin();itr!=li.end();++itr) std::cout << *itr << " "; return 0; }
Output:
5 6 7 8 1 2 3 4
Let's look at a simple example
#include<iostream> #include<list> using namespace std; int main() { list<int> li={9,11,12,13}; list<int> li1={10,6,7,8}; list<int>::iterator itr=li.begin(); list<int>::iterator itr1=li1.begin(); ++itr; li.splice(itr,li1,itr1); for(list<int>::iterator itr=li.begin();itr!=li.end();++itr) std::cout << *itr << " "; return 0; }
Output:
9 10 11 12 13
Let's look at a simple example
#include<iostream> #include<list> using namespace std; int main() { list<string> li={"programming language"}; list<string> li1={"java","is","a","language"}; list<string>::iterator itr = li.begin(); list<string>::iterator itr1=li1.begin(); advance(itr1,3); li.splice(itr,li1,li1.begin(),itr1); for(list<string>::iterator itr=li.begin();itr!=li.end();++itr) std::cout << *itr << " "; return 0; }
Output:
java is a programming language