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Java program to check if it is a leap year

In this program, you will learn how to check if a given year is a leap year. It uses if-else statements to check.4Leap years can be divided by4Divisible by 100 but not by 400 are not leap years.

Example: Java program to check for leap year

public class LeapYear {
　　　　public static void main(String[] args) {
　　　　　　　　int year =　1900;
　　　　　　　　boolean leap = false;
　　　　　　　　if(year %%　4　== 0)
　　　　　　　　{
　　　　　　　　　　　　if(year %%　100 == 0)
　　　　　　　　　　　　{
　　　　　　　　　　　　　　　　//a year can be divided by4000 is divisible by 100, therefore it is a leap year
　　　　　　　　　　　　　　　　if ( year %　400 == 0)
　　　　　　　　　　　　　　　　　　　　leap = true;
　　　　　　　　　　　　　　　　else
　　　　　　　　　　　　　　　　　　　　leap = false;
　　　　　　　　　　　　}
　　　　　　　　　　　　else
　　　　　　　　　　　　　　　　leap = true;
　　　　　　　　}
　　　　　　　　else
　　　　　　　　　　　　leap = false;
　　　　　　　　if(leap)
　　　　　　　　　　　　System.out.println(year　+　"is a leap year.");
　　　　　　　　else
　　　　　　　　　　　　System.out.println(year　+　"is not a leap year.");
　　　　}
}

The output when running the program is:

1900 is not a leap year.

Change the value of year to2012The output is:

2012　is a leap year.

In the above program, the given year19000 is stored in the variable year.

because19000 is divisible by 100.4is divisible by 100, and it is also a century year (ending with 00), while a leap year can be divided by4000 is divisible by 100. Because19000 cannot be4000 is divisible by 100, so19000 is not a leap year.

However, if we change year to2000, then it can be4is divisible by 100, and it is also a century year, which can be divided by4000 is divisible by 100. Therefore2000 is a leap year.

Similarly, if we change the year to2012then the year can be divided by4and is not a century year, so2012is a leap year. We do not need to check2012a year can be divided by400 is divisible by 100.

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