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Java Math Mathematical Methods
Java Math's excludeExact() method subtracts the specified number and returns it.
The syntax of the subtractExact() method is:
Math.subtractExact(num1, num2)
Note: subtractExact() is a static method. Therefore, we can use the Math class name to access this method.
num1 / num2 - To return the first and second values whose difference is to be returned
Note: The data types of these two values should be int or long.
Returns the difference between two values
import java.lang.Math; class Main { public static void main(String[] args) { //Create an int variable int a = 54; int b = 30; //The subtractExact() with integer parameter System.out.println(Math.subtractExact(a, b)); // 24 //Create a long variable long c = 72345678l; long d = 17654321l; //The subtractExact() with long parameter System.out.println(Math.subtractExact(c, d)); // 54691357 } }
In the above example, we used the Math.subtractExact() method with int and long variables to calculate the difference.
If the result of the difference overflows the data type, the excludeExact() method will throw an exception. That is, the result should be within the range of the specified variable's data type.
import java.lang.Math; class Main { public static void main(String[] args) { //Create an int variable. //maximum int value int a = 2147483647; int b = -1; //The subtractExact() with int parameter //throws an exception System.out.println(Math.subtractExact(a, b)); } }
In the above example, the value of a is the maximum int value and the value of b is-1When we subtract a and b,
2147483647 - (-1) => 2147483647 + 1 => 2147483648 //Out of the range of int type
Therefore, the subtractExact() method triggers an integer overflow exception.