Initialize a multidimensional array in C

Variable-size arrays are data structures whose length is determined at runtime rather than compile time. These arrays are very useful in simplifying numerical algorithm programming. C99It is a C programming standard that allows the use of variable-size arrays.

The program demonstrating variable-size arrays in C language is as follows shown-

Example

#include
int main(){
　　　int n;
　　　printf("Enter the size of the array: \n");
　　　scanf("%d", &n);
　　　int arr[n];
　　　for(int \t i=0; \t i<n; \t i++)
　　　arr[i] \t=\t i+1;
　　　printf("The array elements are: \t");
　　　for(int \t i=0; \t i<n; \t i++)
　　　printf("%d \t", arr[i]);
　　　return 0;
}

Output Result

The output of the above program is as follows-

Enter the size of the array:　10
The array elements are:　1　2　3　4　5　6　7　8　9　10

Now let's understand the above program.

The array arr [] is a variable-size array in the above program, because its length is determined by the value provided by the user at runtime. The code snippet is as follows shown:

int n;
printf("Enter the size of the array: \n");
scanf("%d", &n);
int arr[n];

Use a for loop to initialize array elements and then display these elements. The code snippet is as follows-

for(int \t i=0; \t i<n; \t i++)
arr[i] \t=\t i+1;
printf("The array elements are: \t");
for(int \t i=0; \t i<n; \t i++)
printf("%d \t", arr[i]);