Java program to check integer overflow

To check for Integer overflow, we need to check Integer.MAX_VALUE, which is the maximum value of integers in Java.

Let's look at an example where integers are added, and an exception is thrown if the sum is greater than Integer.MAX_VALUE.

Example

public class Demo {
　　　public static void main(String[] args) {
　　　　　　int val1　=　9898989;
　　　　　　int val2　=　6789054;
　　　　　　System.out.println("Value1: "+val1);
　　　　　　System.out.println("Value2: "+val2);
　　　　　　long sum = (long)val1　+　(long)val2;
　　　　　　if (sum > Integer.MAX_VALUE) {
　　　　　　　　　throw new ArithmeticException("Overflow!");
　　　　　　}
　　　　　　//Display the sum
　　　　　　System.out.println("Sum: "+(int)sum);
　　　}
}

Output Result

Value1:　9898989
Value2:　6789054
Sum:　16688043

In the above example, we used the following two integers-

int val1　=　9898989;
int val2　=　6789054;

Now, we will cast and add it to a long.

long sum = (long)val1　+　(long)val2;

If the result is greater than the maximum value, an exception is thrown.

if (sum > Integer.MAX_VALUE) {
　　　throw new ArithmeticException("Overflow!");
}