Method for executing multiple commands continuously in Linux (recommended)

If each command is separated by ";", then regardless of whether the previous command executed successfully or not, the next command will continue to execute

Here, the second command's echo has an extra 'o' intentionally written, causing the command to execute with an error, but it does not affect the execution of subsequent commands

You can think of it this way, if commands are separated by a semicolon, it is equivalent to separating the commands on different lines, and whether the command on the previous line is successful or not will not affect the execution of the next line command.

$ echo 1; echoo 2; echo 3; echo 4
1
-bash: echoo: command not found
3
4

If commands are separated by "&&", then only the command that executed successfully will continue to execute the subsequent command

Here, the second command's echo has an extra 'o' intentionally written, causing the command to execute with an error, echo 3It did not execute, therefore echo4was not executed

$ echo 1 && echoo 2 && echo 3 && echo 4

1
-bash: echoo: command not found

if the commands are separated by "||", then only the command before it fails to continue executing the following command

here echo 1if the commands are separated by "||", then only the command before it fails to continue executing the following command 2, then echo was not executed 3, echo 4

echo 1 || echo 2 || echo 3 || echo 4
1

here echoo 1failed to execute, so started to execute echo 2, execution was successful, so the following echo 3, echo4were not executed
echoo 1 || echo 2 || echo 3 || echo 4
-bash: echoo: command not found
2

Based on the above rules, analyze several special examples, that is, the examples mixed with a variety of separators

echo 1was executed successfully, followed by two "||", so echo 2, echo 3were not executed, afterwards encountered "&&", and the command combination before it was considered to be executed successfully, so echo 4was executed
$ echo 1 || echo 2 || echo 3 && echo 4
1
4

echo 1was executed successfully, followed by echoo 2, execution failed, therefore echo 3was not executed, but afterwards encountered "||", and the previous command combination was considered to be executed failed, so echo 4was executed

$ echo 1 && echoo 2 && echo 3 || echo 4
1
-bash: echoo: command not found
4

echo 1was executed successfully, followed by echoo 2, execution failed, therefore echo 3was not executed, but afterwards encountered ";", which is equivalent to placing the following command on a new line, so no matter how echo 4was executed
$ echo 1 && echoo 2 && echo 3 ; echo 4
1
-bash: echoo: command not found
4

echoo 1failed to execute, followed by "||", so echo 2was executed, echo 2was executed successfully, followed by two "||", so echo 3, echo 4was not executed, but afterwards encountered "&&", and the previous command combination was considered to be executed successfully, so echoo5was executed, the execution occurred with an error, so echo 6was not executed, but there is a ";" afterwards, so no matter how echo 7will be executed
$ echoo 1 || echo 2 || echo 3 || echo 4 && echoo 5 && echo 6 ; echo 7
-bash: echoo: command not found
2
-bash: echoo: command not found
7

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