+= and ++ Simple introduction to operator distinction

We know:

int i = 5;

long j = 7;

i = i + j cannot be compiled, but i += j can be compiled and run, and the result is i = 12.

This is because:

i += j is equivalent to i = (int)(i+j);

In summary, for compound assignment expressions, E1 op= E2 (such as i += j; i -= j etc., is equivalent to E1 = (T)((E1) op (E2)) where, T is E1The type of this element.

This issue has already been answered in the official documentation. Official documentation address §15.26.2 Compound Assignment Operators

The above is what the editor introduces to everyone+= and ++ A simple introduction to the difference between operators, hoping it will be helpful to everyone. If you have any questions, please leave me a message, and the editor will reply to everyone in time. Here we also thank everyone for their support of the Yell Tutorial website!

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