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You can use the following regular expression to match valid phone numbers-
"\\d{10"
A valid phone number usually has10Digit (in India).
The meta-character " \d Matching from 0 to9The number.
The quantifier ex {n} suggests repeating ex n times.
import java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; public class PhoneNumberExample { public static void main(String[] args) { Scanner sc = new Scanner(System.in); System.out.println("Enter your name: "); String name = sc.nextLine(); System.out.println("Enter your Phone number: "); String phone = sc.next(); //Regular expression to accept valid phone number String regex = "\\d{10"; //Creating a pattern object Pattern pattern = Pattern.compile(regex); //Creating a Matcher object Matcher matcher = pattern.matcher(phone); //Verifying whether given phone number is valid if(matcher.matches()) { System.out.println("Given phone number is valid"); } System.out.println("Given phone number is not valid");
Enter your name: krishna Enter your Phone number: 9848022338 Given phone number is valid
Enter your name: krishna Enter your Phone number: 5465 Given phone number is not valid
Enter your name: krishna Enter your Phone number: 984802354655 Given phone number is not valid
import java.util.Scanner; public class Test { public static void main(String[] args) { Scanner sc = new Scanner(System.in); System.out.println("Enter your Phone number: "); String phone = sc.next(); //Regular expression to accept valid phone number String regex = "\\d{10"; //Matching the given phone number with regular expression boolean result = phone.matches(regex); if(result) { System.out.println("Given phone number is valid"); } System.out.println("Given phone number is not valid");
Enter your Phone number: 9848022338 Given phone number is valid
Enter your Phone number: 123 Given phone number is not valid
Enter your Phone number: 123654788755 Given phone number is not valid