Java program to convert byte array to IP address

Given the byte array advertisement, the task is to convert it to an IP address using the IPAddress class in Java and display the result.

What is a byte array

A byte consists of8bits composed of, a byte array is composed of multiple consecutive bytes, which store binary information. In Java, byte is a primitive data type that can be understood as the byte of a computer, that is,8bits, can save-128To127Value.

Declare a byte-byte name_of_byte_variable = initial_value;

Declare a byte array-byte[] name_of_byte_array = new byte[];

What is the IPAddress class

In Java, the IPAddress class is used to get the IP address of any system. It exists in the System.Net class and needs to be imported to use the IPAddress class.

Syntax

IPAddress ObjectName = new IPAddress(byte[])

Example

Input-:　171,　32,　101,　11
Output-:　171.32.101.11
Input-:　172,　31,　102,　14
Output-:　172.31.102.14

The methods we use in the following program are as follows-

• Import class System.net

• Enter numbers as bytes in the byte array

• Create an IPAddress class object and pass an array of bytes to its object

• Use the functionToString()Convert the address to a string representation

• Print Result

Algorithm

START
Step　1-> declare class convert for conversion
　　　public class convert
　　　call class public static void Main() set IPAddress add = new IPAddress(new byte[] {　171,　32,　101,　11　}
　　　　　　　　　call Console.WriteLine(add.ToString())
　　　　　　　　　End
　　　End
STOP

Example

using System;
using System.Net;
public class convert {
　　　public static void Main() {
　　　　　　IPAddress add = new IPAddress(new byte[] {　171,　32,　101,　11　});
　　　　　　Console.WriteLine(add.ToString());
　　　}
}

Output Result

171.32.101.11