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Given number as a string and base; the task is to check if the given number is of the given base.
We must check the number and the base according to the number system, where there is2is a binary number,8is an octal number,10is a decimal number and16is a hexadecimal number. According to this, we must find out if the given number in the string belongs to a specific base, and if it does, we must print 'Yes' on the output screen; otherwise, display 'No' on the output screen.
As we know, the number/The expression “ 1A6” has a base of16while “ 1010” has a base of2But this can be judged by intuitive analysis, now we must find a way to solve this problem. Program.
Input: str = “1010”, base =2 Output: yes Input: str = “1AA4”, base = 16 Output: yes Input: str = “1610”, base = 2 Output: No
The method we will use to solve the given problem-
Check if the base is in2to16between.
Then, check each digit of the string to see if it belongs to a specific base.
If it belongs, return true, otherwise return false.
Start Step 1 -> In function bool isInGivenBase(char str[], int base) If base > 16 then, Return false Else If base <= 10 then, Loop For i = 0 and i < strlen(str) and i++ If !(str[i] >= '0' and str[i] < ('0' + base)), + then, Return false Else Loop For i = 0 and i < strlen(str) and i++ If NOT ((str[i] >= '0' && str[i] < ('0 + base)) || (str[i] >= 'A' && str[i] < ('A + base - 10) ) then, Return false Return true Step 2 -> In function int main() Set str[] = {"AF87"} If isInGivenBase(str, 16) then, Print "yes " Else Print "No " Stop
#include <ctype.h> #include <stdio.h> #include <string.h> bool isInGivenBase(char str[], int base) { //Allowed bases are16(hexadecimal) if (base > 16)) return false; //If the base is less than or equal to10then all // The number of digits should be from 0 to9. else if (base <= 10)) { for (int i = 0; i < strlen(str); i++)) if (!(str[i] >= '0' and str[i] < ('0 + base)) return false; } //If the base is less than or equal to16then all //The number should be from 0 to9or 'A' else { for (int i = 0; i < strlen(str); i++)) if (! ((str[i] >= '0' && str[i] < ('0 + base)) || (str[i] >= 'A' && str[i] < ('A + base - 10)) )) return false; } return true; } // Driver code int main() { char str[] = {"AF87"}); if (isInGivenBase(str, 16)) printf("yes\n"); else printf("No\n"); return 0; }
Output Result
yes