C ++Program checks if the given number is very lucky (all digits are different)

Given a number, the task is to check if the entered number is a lucky number and display the result.

What is a lucky number

A lucky number refers to a number where all digits are different. If at least one digit is repeated, the number will not be considered a lucky number.

Example

Input-: n =　1234
Output-: it is a lucky number
Explanation-: As there is no repeating digit in a number n, so it is a lucky number
Input-: n =　3434
Output-: it is not a lucky number
Explanation-: In the given number n,　3　and　4　are repeating twice, so it is not a lucky number

The methods we use in the given program are as follows-

• Check if the number n entered by the user is a lucky number

• Traverse the entire number until a digit's size

• Mark each visited digit and check if it has been found

• Display whether the given number is a lucky number

Algorithm

Start
Step1-> Declare function to check whether a given number is lucky or not
　　　bool check_lucky(int size)
　　　declare bool arr[10]
　　　Loop For int i=0 and i<10　and i++
　　　　　　Set arr[i] = false
　　　End
　　　Loop While(size > 0)
　　　　　　declare int digit = size %　10
　　　　　　IF (arr[digit])
　　　　　　　　　return false
　　　　　　End
　　　　　　set arr[digit] = true
　　　　　　Set size = size/10
　　　End
　　　return true
Step　2-> In main() Declare int arr[] = {0,34,2345,1249,1232
　　　calculate int size = sizeof(arr)/sizeof(arr[0])
　　　Loop For int i=0 and i<size and i++
　　　　　　check_lucky(arr[i])?
　　　　　　print is Lucky : print is not Lucky
　　　End
Stop

Example

#include<iostream>
using namespace std;
//If there is a number, return true.
bool check_lucky(int size) {
　　　　bool arr[10];
　　　　for (int i = 0; i <10; i++)
　　　　　　　　arr[i] = false;
　　　　while (size > 0) {
　　　　int digit = size %　10;
　　　　　　if (arr[digit])
　　　　　　　　　　　return false;
　　　　　　　　arr[digit] = true;
　　　　　　　　size = size/10;
　　　　
　　　　return true;

int main() {
　　　　int arr[] = {0,34,2345,1249,1232};
　　　　int size = sizeof(arr);/sizeof(arr[0]);
　　　　for (int i = 0; i < size;++)
　　　　　　　　check_lucky(arr[i]) ? cout << arr[i] << " is Lucky \n" : cout << arr[i] << " is not Lucky \n";
　　　　return 0;

Output Result

19　is Lucky
34　is Lucky
2345　is Lucky
1249　is Lucky
1232　is not Lucky