Java Program to Multiply Integers and Check for Overflow

To check for Integer overflow, we need to check the result of multiplying Integer.MAX_VALUE by an integer, here, Integer.MAX_VALUE is the maximum value of integers in Java.

Let's look at an example where integers are multiplied, and if the result is greater than Integer.MAX_VALUE, an exception will be thrown.

The following is an example of how to check for Integer overflow.

Example

public class Demo {
　　　public static void main(String[] args) {
　　　　　　int val1　=　9898;
　　　　　　int val2　=　6784;
　　　　　　System.out.println("Value1: "+val1);
　　　　　　System.out.println("Value2: "+val2);
　　　　　　long mul = (long)val1　*　(long)val2;
　　　　　　if (mul > Integer.MAX_VALUE) {
　　　　　　　　　throw new ArithmeticException("Overflow!");
　　　　　　}
　　　　　　//Display Multiplication
　　　　　　System.out.println("Multiplication Result: "+(int)mul);
　　　}
}

Output Result

Value1:　9898
Value2:　6784
Multiplication Result:　67148032

In the above example, we use the following two integers.

int val1　=　9898;
int val2　=　6784;

Now, we project and double it.

long mul = (long)val1　+　(long)val2;

If the result is greater than the maximum value, an exception is thrown.

If (mul > Integer.MAX_VALUE) {
　　　throw new ArithmeticException("Overflow!");
}