Java Program to Subtract Integer and Check Overflow

To check for Integer overflow, we need to use the result of the subtracted integer to check Integer.MAX_VALUE. Here, Integer.MAX_VALUE is the maximum value of integers in Java.

Let's look at an example where an integer is subtracted, and if the result is greater than Integer.MAX_VALUE, an exception will be thrown.

The following is an example of how to check for Integer overflow.

Example

public class Demo {
　　　public static void main(String[] args) {
　　　　　　int val1　=　9898999;
　　　　　　int val2　=　8784556;
　　　　　　System.out.println("Value1: "+val1);
　　　　　　System.out.println("Value2: "+val2);
　　　　　　long sub = (long)val1　-　(long)val2;
　　　　　　if (sub > Integer.MAX_VALUE) {
　　　　　　　　　throw new ArithmeticException("Overflow!");
　　　　　　}
　　　　　　//Display the subtraction result
　　　　　　System.out.println("Subtraction Result: "+(int)sub);
　　　}
}

Output Result

Value1:　9898999
Value2:　8784556
Subtraction Result:　1114443

In the above example, we use the following two integers-

int val1　=　9898999;
int val2　=　8784556;

Now, we convert it to subtraction.

long sub = (long)val1　-　(long)val2;

If the result is greater than the maximum value, an exception is thrown.

If (sub > Integer.MAX_VALUE) {
　　　throw new ArithmeticException("Overflow!");
}